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Computing

Petals Around the Rose: Fraternity Register

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juan 
Location:
argentina
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IP logged  Mozilla/5.0 (Windows; U; Windows NT 5.1; es-AR; rv:1.7.5) Gecko/200411  #2887
Tuesday, 8 March 2005 03:55 PM  

I´ve found a mathematical solution... please, someone has to tell me the easy answer...
I´ve noticed that when a 3 or a 5 is on the dice you have to rest one unit from those... and the other dice you have to eliminate them
example:
3 3 1 6 1 = 4
it would be like this
2 2 --(1 6 1)-- = 2 + 2= 4
another example
5 5 5 3 2 = 14
4 4 4 2 --(2)-- = 4 + 4 + 4 + 2 = 14

try it!!!
and please tell me the easy solutionn...
i´ve been hours trying
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