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Computing

Petals Around the Rose: Fraternity Register

Sunday, 26 July 2026 01:10 AM Please Sign the Register    Administration Centre
If you have truly qualified to join the Fraternity of Petals Around the Rose by solving this challenge, please make sure you sign the register.
Total Entries: 11696   Entries Viewed Per Page: 10  1 ... 361 362 [363] 364 365 ... 1170
Name Comments
Dennis Pham  Male
Location:
New York City 
USA USA  
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IP logged  Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; .NET CLR 1.1.4322; .NET CLR 2.0.50727; InfoPath.2)  #8076
Wednesday, 6 December 2006 02:30 AM  

it took me about 30mins. big grin woohooo!!! finally figured it out
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Steven Kovalesky 
Location:
Tujunga, CA 
USA USA  
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IP logged  Mozilla/5.0 (Macintosh; U; Intel Mac OS X; en) AppleWebKit/418.9.1 (KHTML, like Gecko) Safari/419.3  #8075
Wednesday, 6 December 2006 01:01 AM  

roll eyes (sarcastic) "What forest?" roll eyes (sarcastic)
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brenda  Female
Location:
anahola, hawaii 
USA USA  
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IP logged  Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322)  #8074
Wednesday, 6 December 2006 12:42 AM  

First try about and hour, went to bed next morning 20 minutes.. big grin big grin
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ivan the fearsome 
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IP logged  Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.0.8) Gecko/20061025 Firefox/1.5.0.8  #8073
Wednesday, 6 December 2006 12:01 AM  

The "rose" is the center dot on any face that has one (i.e. 1, 3, and 5) and the "petals" are all dots around it -- the 1 face has no petals, the 3 face has two petals and the 5 face has four petals. The die faces without center dots (i.e. 2, 4, and 6) do not count. Counting the total petal dots yields that round's answer.

Alternately, one may sum the faces of odd dice, and then subtract the number of them. Thus, in a roll of 1, 3, 4, 5, and 3, the odd faces sum to 12. There are four odd dice, so the solution is 12-4, or 8.
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Ray  Male
USA USA  
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IP logged  Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1) Gecko/20061010 Firefox/2.0  #8072
Tuesday, 5 December 2006 09:35 PM  

got this in 7 minutes
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Joanna Hobbins  Female
Location:
Montreal, Quebec 
Canada Canada  
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IP logged  Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1) Gecko/20061010 Firefox/2.0  #8071
Tuesday, 5 December 2006 09:23 PM  

I confess it only took two dice rolls.
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al couto  Male
Location:
hopewell junction 
USA USA  
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IP logged  Mozilla/4.0 (compatible; MSIE 7.0; AOL 8.0; Windows NT 5.1; FunWebProducts; .NET CLR 2.0.50727; ZangoToolbar 4.8.3)  #8070
Tuesday, 5 December 2006 07:04 PM  

GREAT BRAIN TEASER I LOOKED AT IT AT WORK FOR A WHILE IT DROVE ME NUTS SO I STOPPED. WHEN I GOT HOME I LOOKED AT IT AGAIN AND GOT IT IN ABOUT 10 MIN.
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Derek Cardenas  Male
Location:
seattle 
USA USA  
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IP logged  Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1) Gecko/20061010 Firefox/2.0  #8069
Tuesday, 5 December 2006 06:22 PM  

i got this in about half an hour to 45 minutes, i guess my simple little mind helped me out for once!! smile
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chad Selph  Male
Location:
Pullman, WA 
USA USA  
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IP logged  Mozilla/5.0 (Macintosh; U; Intel Mac OS X; en) AppleWebKit/418.9 (KHTML, like Gecko) Safari/419.3  #8068
Tuesday, 5 December 2006 04:56 PM  

aahh I spent about an hour last night trying to figure this out... I had this complex mathematical way of doing it that worked between 1/2 and 1/3 of the time.

But today it took me 3 tries and suddenly it was obvious!

fun game, so satisfying!
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Gerry  Male
Location:
Maine 
USA USA  
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IP logged  Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322; .NET CLR 2.0.50727)  #8067
Tuesday, 5 December 2006 04:55 PM  

bounce
I guess I went through 100 tries. Thinking too hard. Now I'm off to work to see how many I can hook
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